The relative atomic mass of naturally occurring lithium consisting of 90% 7Li and 10% 6Li is
6.2
6.9
6.8
7.1
0
Step-by-step calculation:
\[ A_r = \frac{(90 \times 7) + (10 \times 6)}{100} \]
\[ A_r = \frac{630 + 60}{100} = \frac{690}{100} = 6.9 \]
Final Answer: 6.9
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