Given that M is the mass of a substance deposited during electrolysis and Q is the quantity of electricity consumed, then Faraday's first law can be written as [Electrochemical equivalent]
\(M = \dfrac{E}{Q}\)
\(M = EQ\)
\(M = \dfrac{Q}{E}\)
\(M = \dfrac{E}{2Q}\)
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Step 1. Recall Faraday’s first law of electrolysis:
The mass of a substance deposited (\(M\)) during electrolysis is directly proportional to the quantity of electricity (\(Q\)) passed through the electrolyte.
\( M \propto Q \)
Step 2. Introduce the constant of proportionality:
\( M = EQ \)
Here, \(E\) is the electrochemical equivalent (ECE) of the substance. It depends on the substance’s molar mass and valency, and has units of mass per unit charge (g C\(^{-1}\)).
Step 3. Match with the options:
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