An organic compound has an empirical formula CH2O and vapour density of 45. What is the molecular formula? [C = 12, H = 1, O = 16]
C3H7OH
C2H5OH
C3H6O3
C2H4O2
0
Step 1. Use vapour density: For gases, \( \text{Molar mass} = 2 \times \text{vapour density} \).
So \( M = 2 \times 45 = 90\ \text{g mol}^{-1} \).
Step 2. Empirical formula mass (EFM): For CH\(_2\)O, \( \text{EFM} = 12 + 2(1) + 16 = 30 \).
Step 3. Find the multiple: \( n = \dfrac{M}{\text{EFM}} = \dfrac{90}{30} = 3 \).
Step 4. Molecular formula: \( (\text{CH}_2\text{O}) \times 3 = \text{C}_3\text{H}_6\text{O}_3 \).
Don't miss the opportunity to help others. Register or log in to add a solution!
Help the community by answering some questions.
