Two organic compounds K and L were treated with a few drops of Fehling's solutions respectively. K formed a brick red precipitate while L, remains unaffected. The compound K is an
alkanol
alkane
alkanal
alkanone
0
Explanation: Fehling’s solution (alkaline Cu2+ complex) is reduced by aldehydes to brick-red Cu2O while the aldehyde is oxidized to a carboxylate. Ketones, alkanols, and alkanes do not give this brick-red precipitate under Fehling’s test. Therefore, the compound that reacts (K) must be an alkanal (aldehyde).
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