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Question from: Chemistry

During a titration experiment, 0.05 moles of carbon(IV) oxide is liberated. What is the volume of gas liberated at s.t.p.?

A)  

22.40 dm³

B)  

11.20 dm³

C)  

2.24 dm³

D)  

1.12 dm³

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juanbacan

hace 14 días

Solution

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Correct answer: 1.12 dm³ (Option D)

Explanation: At s.t.p., 1 mole of any ideal gas occupies 22.4 dm³. Therefore, for 0.05 mol:

\(\text{Volume} = 0.05 \times 22.4 = \mathbf{1.12\ \text{dm}^3}\).

  • 22.40 dm³ – volume of 1.00 mol, not 0.05 mol.
  • 11.20 dm³ – volume of 0.50 mol.
  • 2.24 dm³ – volume of 0.10 mol.
  • 1.12 dm³ – correct for 0.05 mol.

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