A piece of filter paper moistened with lead (ll) ethanoate solution turns black when the paper is dropped into a gas likely to be
sulphur(VI) oxide
hydrogen chloride
sulphur (VI) oxide
hydrogen sulphide
0
Correct answer: hydrogen sulphide (H2S).
Explanation: Lead(II) ethanoate (“lead acetate”) paper is a classic test for H2S. The gas reacts to form black lead(II) sulphide:
Pb(CH3COO)2(aq) + H2S(g) → PbS(s)↓ + 2 CH3COOH(aq)
Don't miss the opportunity to help others. Register or log in to add a solution!
Help the community by answering some questions.