Ethanol reacts with concentrated tetraoxosulphate(VI) acid at a temperature above 170°C to form
ethanone
ethene
ethyne
ethanal
0
Correct answer: ethene.
Explanation: Concentrated H2SO4 at temperatures above about 170 °C dehydrates ethanol, eliminating water to form an alkene:
\(\text{C}_2\text{H}_5\text{OH} \;\xrightarrow[\;>170^\circ\text{C}\;]{\text{conc. } \text{H}_2\text{SO}_4}\; \text{C}_2\text{H}_4 + \text{H}_2\text{O}\)
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