The final products of the reaction between methane and chlorine in the presence of ultraviolet light are hydrogen chloride and

Correct answer: tetrachloromethane (CCl₄).

Explanation: Under UV light, methane undergoes free-radical substitution with chlorine. Successive substitutions replace all four H atoms, forming a series of products:

CH₄ → CH₃Cl → CH₂Cl₂ → CHCl₃ → CCl₄

With excess Cl₂ and continued irradiation, the final organic product is tetrachloromethane, and HCl is produced at each substitution step.

• Chloromethane (CH₃Cl), dichloromethane (CH₂Cl₂), and trichloromethane (CHCl₃) are intermediate products, not the final one under excess chlorine.