The correct order of increasing boiling points of the following compounds C₃H₇OH, C₇H₁₆ and C₄H₁₀ is

Correct answer: C₄H₁₀ → C₇H₁₆ → C₃H₇OH (Option B)

Explanation: Boiling point increases with stronger intermolecular forces:

• C4H10 (butane): small non-polar molecule → weakest London forces → lowest b.p.
• C7H16 (heptane): larger non-polar molecule → stronger London forces than C4H10 → higher b.p. than butane.
• C3H7OH (propanol): polar alcohol capable of hydrogen bonding → highest b.p. of the three.