No subcategories

Question from: Chemistry

Three drops of a 1.0 mol dm−3 solution of HCl were added to 20 cm3 of a solution of pH 6.4. The pH of the resulting solution will be

A)  

Close to that of pure water

B)  

Less than 6.4

C)  

Greater than 6.4

D)  

Unaltered

Solutions

j

juanbacan

hace 12 días

Solution

0

Correct answer: Less than 6.4

Explanation: Adding a strong acid (HCl) increases the hydrogen-ion concentration, so the pH must decrease. Here, even a few drops of 1.0 mol dm−3 HCl contain far more H+ than was originally present in 20 cm3 of a pH 6.4 solution (which has only about 4×10−7 mol dm−3 H+). Therefore, the resulting solution is more acidic, with pH < 6.4 (often much lower, unless the solution is buffered).

  • Close to that of pure water — Incorrect; adding strong acid won’t give pH ≈ 7.
  • Less than 6.4Correct.
  • Greater than 6.4 — Incorrect; that would mean becoming less acidic.
  • Unaltered — Incorrect; pH changes on adding strong acid (no buffer stated).

Add a solution

Don't miss the opportunity to help others. Register or log in to add a solution!

Show your knowledge

Help the community by answering some questions.

Practice with Simulators

Test your knowledge, solve these simulators similar to the exam

Do you need help with an exercise?

Ask a question and all of us in this community will answer it.

Ask